{1000}\)= 0.0075 mol moles of sulfuric acid = \(\frac{0.0075}{2}\)= 0.00375 mol (as 2:1 ratio of NaOH:H 2 SO 4) Rearranging the equation above gives:\(volume = \frac {moles × 1000}{concentration}\) ...

Molarity equations To calculate molarity or to calculate related values (including volume, mass, molar mass and concentration) from molarity, the following equations are utilized. So, to make 2 liters ...

The molar ratio of nitrogen to ammonia from the balanced equation is 1:2. This means that if 400 cm 3 of nitrogen are used then we will form double that volume of ammonia.

Air is about 79% nitrogen by volume and 21% oxygen by volume. For a stoichiometric combustion reaction in this case each mole of oxygen will be accompanied by 3.76 moles of nitrogen. The reaction ...

Molarity equations To calculate molarity or to calculate related values (including volume, mass, molar mass and concentration) from molarity, the following equations are utilized. So, to make 2 liters ...